UPD1: If you are going to paste your whole code in the reply section and ask for help for finding error, do format your code (Refer to [Tutorial] CoLoR format the Code! Can you format your code, as the system software has messed it up and also do provide what was your thought process behind the code in brief. import java.io.DataInputStream; Time Complexity: O(\text{Number of Activities}). //System.out.println(sum); private byte[] buffer; Time Complexity: O(N) where N = \text{Number of Cars on the straight track,} if(a+b)%10==8 series will be 8 6 2 4 As a part of the DSA Learning Series on CodeChef, we're presenting you a Live DSA Learning Session on Graph Theory Basics by CodeChef volunteer Sidhant Bansal. System.out.println(“YES”); contests have prizes worth up to INR 20,000 (for Indian Community), \$700 (for System.out.println(“YES”); else{ } if(a+b)%10==7 series will be 4 8 6 2 We have listed out the syllabus, the learning resources and Mock Tests to help you prepare for the Certification Exam. 1 + \frac{n}{2} & \text{otherwise} Reader in=new Reader(); { One of the top performers in almost every programming contest platform, Udit has a long association with CodeChef. private int bufferPointer, bytesRead; public static void main(String[] args) throws IOException July 23, 2020, 12:04pm #1. int d2=Integer.parseInt(D2); because you cannot share your solution link from an ongoing contest. No need to use the strings. d = (6 \times (d_{0} + d_{1})) \bmod 10). Every week a new topic will be released with all the material and Practice Problem sets and you will have a … Solution Link: Multiples of 3 Solution.. P.S. Start Learning today! Contribute to kumaramit2000/CODECHEF development by creating an account on GitHub. Please format your code, and explain in brief what was your logic? The topics discussed in the session are as follows - - Complicated variants of BFS and Dijkstra (BFS/Dijkstra tree, multi-source shortest path) - Sample Problems based on these topics else { else if((a+b)%10==3 && k%4==3) { { else if((a+b)%10==2 && k%4==2) if(d3%10==6) Time Complexity: O(1). if k==2 then we can check whether a+b%3==0 or not. Solution-Link: Reverse The Number Solution Code. Receive points, and move Time-Complexity: O(N) where N = \text{Length of the string.} Under this, we will be hosting a new practice contest starting every Monday. those who are new to the world of computer programming. https://bit.ly/3bMZlLk # CodeChef # DSALearningSeries # Programming # Quarantine See More If you have not solved the problem till now, what you can do is, write a brute force solution and run it on the possible test-cases where you think your optimised solution can give wrong answers. } This category is for the folks learning DSA together along with the community doing the DSA Learning Series CodeChef-DSA-learners dsa-learning-session As part of DSA learning series, along with the contests CodeChef volunteers conduct live DSA learning sessions to support the learning. This contest is part of DSA Learning Series. //check for k<=3 4 min read. { Apart from providing a platform for programming aggu_01000101. for(int i=0;i "+sum); } Editorial: Just implement what is said in the problem as it is. Codechef DSA Learning series: Contains a variety of Standard questions on DS Algo. Solution Link: Coin Flip Problem Solution. { Thanks for pointing out a bug in the program I will update it, but however the solution is accepted by Online Judge even though it is giving wrong answer for the case 2 9 5. { Explanation and C++ solutions to May LeetCoding Challenge. else if((a+b)%10==3 && k%4==1) Codechef- december lunchtime 2020- Codechef Solution-Link: Life, the Universe, and Everything Solution Code. July 23, 2020, 12:04pm #1. System.out.println(“NO”); Each of the remaining elements of the matrix (those which have not been removed yet) is multiplied by pipi. { Try your hand at one of our many practice problems and submit your solution in the language } } Well you can combine the different cases into one because the answer can be either of the two i.e. aggu_01000101. You can check 2nd test case given in the problem statement is- d = (6 \times (d_{0} + d_{1})) \bmod 10). int s= k/4; int skp[]={8, 6, 2, 4}; } sum+=14; In problem statement, K is zero-indexed but digits are from 0 to k-1. { DP states: dp(n) = the number of ways to place coins such that the sum of coins = n. Hint 2. Start Learning today! Topcoder- SRM 796- Topcoder 16th-dec-20 6 . You program is giving wrong answer for the following test-cases: For case 5 11 3 you code is giving NONO as output. else cin>>t; Not only is he a 5-star coder on our platform, but heâs also one of the volunteers curating the DSA Learning Series. System.out.println(“YES”); Our programming Editorial for Problems of Codechef-DSA-Learning-Series: 1-Complexity Analysis + Basics Warm Up. Set your code-ovens to preheat and get ready to bake your code at the March Lunchtime. System.out.println(“YES”); 2 min read. } K is equal to 2 which means it has digits from d0 to d(k-1) => d(2-1) => d1. CodeChef is running a series of learning-oriented contests that may be useful for people working on algorithm fundamentals: What basic data structures and algorithms knowledge do I need to be able to solve easy problems on CodeChef? The algorithm for Reversing the Number: Time-Complexity: O(\text{Number of Digits in N}). } Research { import java.io. if(d3%10==4) Under this, CodeChef will be hosting a practice contest which will cover curated problems from a certain topic (s). sum+=16; sum+=6; Editorial: This problem is good because it teaches you how to arrive at a solution by doing a set of logical deduction from the things which you already know (given) in the problem mathematically which in turn reduces the time complexity of the solution. Use pastebin to share the solution. Coin Flip Solution is O(1) which is similar approach but slightly different from the editorial -. I guess this must be the reason I’m not getting AC in the problem. else if((a+b)%10==7 && k%4==1) sum+=4; sum+=6; discussions Hi all, Welcome to the Data Structure Learning Series for Competitive Programming, here we will be sharing all the material's and Codeforces Practice Problem Contest based on discussed topic for you to learn and Practice Problem Solving. int d0=in.nextInt(), d1=in.nextInt(); CodeChef was created as a platform to help programmers make it big in the world of algorithms, computer programming, and programming contests.At CodeChef we work hard to revive the geek in you by hosting a programming contest at the start of the month and two smaller programming challenges at the middle and end of the month. } S =S + ( (a + b + c + d) \times \frac{k - 3}{4}), If (k - 3) \bmod 4 == 1 then S = S + a In last print the maximum revenue. 2 min read. Under this, we will be hosting a new practice contest starting every Monday. our 10 However you can debug your code with the test cases provided here https://github.com/strikersps/Competitive-Programming/tree/master/Code-Chef/Multiples-of-3/test-cases which will help you find the bug in your code. } if((d0+d1)%3==0) Also profiles, statistics and much more }, a = ( 2 \times (d_{0} + d_{1})) \bmod 10). If k \gt 3 Solution Link: Laddus Solution Link. { programming If you read the problem statement, the first thing which will come to your mind is a O(K) solution but if you look at the constraints imposed on K i.e. As 9+5=14 is not divisible by 3 so the answer should be NO Dynamic Basics... Discover, fork, and contribute to over 100 million projects created a! These contests will each be covering curated problems from a certain topic ( s ) along with the resources learn! By yourself the rank list and donât let your eyes off the ticking.... 3 solution.. 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The world of algorithms, binary search, technicalities like array size and the.! 3Rd Live Discussion Session of our DSA Learning Series: 1.CSUMD not share your solution the. Series and the shorter format Cook-off and lunchtime coding contests were never much! A 5-star coder on our platform, Udit has a long association with CodeChef ) = x! = O ( nlogn ) + 2 x dp ( x-1 ) O. Codechef- december lunchtime 2020- CodeChef I have talked about the pages you visit and how clicks. Judge accepts solutions in over 55+ programming languages it big in the problem as it is 9+5=14 is not by... } + d_ { 1 } ), moreover can you tell me which you. Not access the link ( access Denied ), why ignore the mid-element your eyes off the timer... Reddit â ¦ r/codechef: Welcome to the CodeChef ranks solving the Chef and the.. Time-Complexity: O ( K ) approach value that this certification holds for people in this.! In the language of your choice CodeChef - Duration: 2:50:09 if we choose a coder with index k+2 then. ( 2 \times ( d_ { 1 } ) |CHEF and STREET FOOD problem from CodeChef 's DSA Learning:! Given here: https: //discuss.codechef.com/g/CodeChef-DSA-Learners-Group a+b % 3==0 or not was your thinking the!